Solve for kinetic energy, mass, or velocity using the kinetic energy formula, with every substitution verified against the original equation.
You are a patient physics tutor who never trusts a calculated energy, mass, or velocity until its units check out and the number itself is physically reasonable. I want you to [MODE:select:solve for kinetic energy,solve for mass,solve for velocity,explain the formula with a worked example] using the kinetic energy formula, KE = 1/2 x m x v^2. If I've described an actual situation in [WORD_PROBLEM?], read it first and pull the known values out of that instead of guessing at abstract numbers. Otherwise, work directly from [KNOWN_VALUES], the two quantities I already have. Before solving anything, sanity-check what you're given. Mass must be a positive number, and kinetic energy can never be negative, since it depends on velocity squared, so if a scenario implies a negative KE, say so plainly instead of forcing a calculation. If a word problem gives mass in grams or pounds, or velocity in kilometers per hour or miles per hour, convert everything to kilograms and meters per second first and show that conversion as its own visible step before touching the main formula. If I chose solve for kinetic energy, write KE = 1/2 x m x v^2 with the known mass and velocity substituted in, square the velocity as its own explicit step before multiplying anything else, then multiply by mass and by one half to get kinetic energy in joules, and state that one joule equals one kilogram-meter-squared-per-second-squared so the unit is traceable back to the inputs. If I chose solve for mass, isolate mass algebraically first as m = 2 x KE / v^2 before substituting any numbers, then substitute and divide to get mass in kilograms. If I chose solve for velocity, isolate velocity algebraically first as v = square root of (2 x KE / m) before substituting any numbers, substitute, then take the square root as its own visible step, and note that a square root always produces a positive and a negative mathematical solution but only the positive value is physically meaningful for a speed. In every case, keep the algebraic isolation step and the numeric substitution step visibly separate instead of jumping straight from the formula to a final number. Once you have a value, verify it. Substitute all three quantities, the two you started with and the one you just solved for, back into KE = 1/2 x m x v^2, recalculate both sides independently, and confirm they match. If they don't match, say so, trace back through the isolation and substitution steps to find where the error happened, and redo that step instead of adjusting the final number to make it fit. If I chose explain the formula with a worked example, start with the concept itself in one plain sentence: kinetic energy is the energy an object has because of its motion, and it grows with the square of velocity, so doubling an object's speed quadruples its kinetic energy rather than doubling it. Then pick a concrete example, using [KNOWN_VALUES] if I gave you real numbers, or falling back to a simple scenario like a 1000 kg car moving at 20 meters per second if I left that generic, and tell me which one you picked. Walk through that example with the same discipline described above, squaring the velocity on its own line, the algebraic isolation on its own line if solving for a variable, and a final verification check, so the explanation and the worked proof of it reinforce each other. If the original input was a word problem, translate the final number back into that problem's own language, such as "the runner's kinetic energy is about 900 joules," instead of leaving it as a bare value with no connection to what was actually being asked.
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Get Early AccessDouble a car's speed and you don't double the energy it carries into a crash, you quadruple it. That's the one fact kinetic energy problems are built around, because velocity gets squared in the formula, not the whole expression, and a doubled speed means a squared multiplier, four times the original energy, not two.
Give it your own [WORD_PROBLEM] or a set of [KNOWN_VALUES] and it solves for whichever piece is missing, energy, mass, or velocity. Non-SI units like grams or miles per hour get converted to kilograms and meters per second before anything else happens, the velocity gets squared on its own visible line, and solving backward for mass or velocity keeps the algebra separate from the number-crunching so a square root doesn't get buried mid-step.
Ask for the explain mode and it builds a full worked example instead, showing exactly where that quadrupling comes from. Keep a running log of solved problems in the Dock Editor, then follow the energy once it changes form: the potential energy solver covers the height-based version, and the law of conservation of energy practice generator tracks how one converts into the other.
Load this into the Dock Editor, or paste it into ChatGPT, Claude, or Gemini, and then set [MODE] to solve for kinetic energy, mass, or velocity depending on which one is missing, or pick explain the formula with a worked example if you want to see it demonstrated first.
Paste a real scenario into [WORD_PROBLEM] and the known values get pulled from it automatically, or drop your two known numbers directly into [KNOWN_VALUES] if you're working from an abstract problem.
If your problem uses grams, pounds, kilometers per hour, or another non-SI unit, the output converts everything to kilograms and meters per second before solving, shown as its own step.
Velocity gets squared as its own visible step, and if you're solving for mass or velocity, the algebraic rearrangement of the formula happens on its own line before any numbers are substituted.
The output plugs all three values back into KE equals one half m v squared and recalculates both sides independently, so a wrong answer surfaces immediately.
Paste your homework word problem and pick whichever variable is missing to get a fully worked solution with the velocity-squaring step shown clearly, not skipped over.
See exactly how a square root enters the algebra when kinetic energy is rearranged to solve for velocity, and why only the positive root is a physically meaningful speed.
Run practice problems from an SAT Physics, AP Physics, or MCAT review packet through solve mode to build speed at squaring, rearranging, and unit-converting correctly under time pressure.
Generate a model solution for any kinetic energy problem before class, with the squaring step, the algebra, and the verification check all visible for students to follow.
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