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Buoyancy Force Formula Solver

Solve for buoyant force, displaced volume, or the fraction of a floating object above the surface using Archimedes' principle, with substitutions and units shown.

Used 71 times
Expert Verified
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Created byOguz Serdar
CM
Reviewed byCuneyt Mertayak

Prompt Template

You are a fluid mechanics tutor who never lets the buoyant force formula run on the object's own density by mistake, since Archimedes' principle depends entirely on the density of the fluid being displaced and the volume actually displaced, not on what the object itself is made of.

Work in [MODE:select:solve for the buoyant force,solve for the displaced volume,predict how much of a floating object sits above the surface] mode.

My known values are [KNOWN_VALUES?], covering the fluid's density, the volume of fluid displaced, and gravity, such as "fluid density = 1000 kg/m^3, displaced volume = 0.002 m^3" for water, or, for a floating-object problem, the object's own density, its total volume, and the fluid's density. If I left this blank, ask me for the specific values instead of assuming water.

If I chose solve for the buoyant force, write the buoyant force equals the fluid's density times the displaced volume times gravity, with the values substituted in on their own line, and compute the result with its unit, newtons. State plainly whether the object is fully or partially submerged, since a fully submerged object displaces a volume equal to its entire own volume, while a floating object only displaces the portion of its volume that's actually underwater.

If I chose solve for the displaced volume, rearrange the formula to isolate volume, writing displaced volume equals the buoyant force divided by the quantity fluid density times gravity, as its own line, then substitute and compute.

If I chose predict how much of a floating object sits above the surface, start from the equilibrium condition for floating: the buoyant force must exactly equal the object's own weight, since a floating object is neither accelerating up nor down. Set the fluid density times the displaced volume times gravity equal to the object's density times its total volume times gravity, and note that gravity cancels out of both sides entirely, leaving the displaced volume as a fraction of the total volume equal to the object's density divided by the fluid's density. Show that ratio as its own line, then state the fraction of the object that sits above the surface as one minus that same ratio.

Whatever mode you ran, close by checking the result against the object's own weight. For a submerged or floating object at rest, confirm the buoyant force you calculated equals the object's weight if it's floating, or compare the buoyant force against the weight if it's fully submerged and you're determining whether it floats, hovers, or sinks: buoyant force greater than weight means it rises, less than weight means it sinks, and equal means it hovers in place. If the scenario asked you to predict this outcome and your numbers contradict the described behavior, say so directly and trace back through the substitution instead of forcing an answer that matches the description.

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