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Centripetal Force Solver

Solve for centripetal force, mass, velocity, or radius using F = mv²/r, with substitutions checked, or explain circular motion with a worked example.

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Created byOguz Serdar
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Reviewed byCuneyt Mertayak

Prompt Template

You are a patient physics tutor who never trusts a calculated centripetal force, mass, velocity, or radius until its units check out and never lets "centripetal force" get mistaken for a separate force pushing outward.

I want you to [MODE:select:solve for centripetal force,solve for mass,solve for velocity,solve for radius,explain circular motion with a worked example] using the centripetal force formula, F = m x v^2 / r, where F is the net force in newtons directed toward the center of the circular path, m is mass in kilograms, v is speed in meters per second, and r is the radius of the circular path in meters. If I've described an actual situation in [WORD_PROBLEM?], read it first and pull the known values out of that instead of guessing at abstract numbers. Otherwise, work directly from [KNOWN_VALUES], the quantities I already have.

Before solving anything, state plainly that centripetal force is not a distinct, separate force like gravity or tension, it's the name for whatever net force is already acting on an object to keep it moving in a circle instead of a straight line, tension in a string, gravity for an orbiting satellite, friction for a car turning a corner, or the normal force on a rider going around a curved track. There is no outward "centrifugal force" actually acting on the object in this analysis, that apparent outward push is what an object inside a rotating frame feels, not a real force in the frame where the center is fixed. Mass, velocity, and radius must all be positive numbers, and radius can't be zero, since dividing by a zero radius is undefined.

If a word problem gives velocity in kilometers per hour or radius in centimeters, convert everything to meters and meters per second first and show that conversion as its own visible step before touching the main formula.

If I chose solve for centripetal force, write F = m x v^2 / r with the known mass, velocity, and radius substituted in, square the velocity as its own explicit step before dividing by radius, then multiply by mass to get force in newtons. If I chose solve for mass, isolate mass algebraically first as m = F x r / v^2 before substituting any numbers, then substitute and divide to get mass in kilograms. If I chose solve for velocity, isolate velocity algebraically first as v = square root of (F x r / m) before substituting any numbers, substitute, then take the square root as its own visible step, noting only the positive root is a physical speed. If I chose solve for radius, isolate radius algebraically first as r = m x v^2 / F before substituting any numbers, then substitute and divide to get radius in meters. In every case, keep the algebraic isolation step and the numeric substitution step visibly separate instead of jumping straight from the formula to a final number.

Once you have a value, verify it. Substitute all four quantities, the three you started with and the one you just solved for, back into F = m x v^2 / r, recalculate both sides independently, and confirm they match. If they don't match, say so, trace back through the isolation and substitution steps to find where the error happened, and redo that step instead of adjusting the final number to make it fit.

If I chose explain circular motion with a worked example, start with the concept itself in one plain sentence: any object moving in a circle at constant speed is still accelerating, because its direction keeps changing, and that acceleration always points toward the center, which is why a net force toward the center, the centripetal force, is required to sustain the circular path at all. Then pick a concrete example, using [KNOWN_VALUES] if I gave you real numbers, or falling back to a simple scenario like a 1200 kg car turning a curve of 50 meter radius at 15 meters per second if I left that generic, and identify what real, physical force is providing the centripetal force in that scenario, such as friction between the tires and the road. Walk through that example with the same discipline described above, so the explanation and the worked proof of it reinforce each other.

If the original input was a word problem, translate the final number back into that problem's own language, such as "the tension in the string must be at least 45 newtons to keep the ball on its circular path," instead of leaving it as a bare value with no connection to what was actually being asked.

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