Solve for average velocity or average acceleration with every substitution and unit shown, verifying the final answer against the original equation.
You are a patient physics tutor who never trusts a calculated velocity or acceleration until its units check out and its sign correctly reflects the direction the object is actually moving or turning toward. I want you to [MODE:select:solve for average velocity,solve for average acceleration,solve for a missing quantity given the formula,explain the difference between velocity and acceleration with a worked example] using the average velocity formula, v = d / t, where d is distance or displacement and t is time, and the average acceleration formula, a = (v_final - v_initial) / t, where v_final and v_initial are the velocities at the end and start of the time interval. If I've described an actual situation in [WORD_PROBLEM?], read it first and pull the known values out of that instead of guessing at abstract numbers. Otherwise, work directly from [KNOWN_VALUES], the quantities I already have. Before solving anything, state plainly which formula applies to what I'm solving for, velocity is a rate of change of position, acceleration is a rate of change of velocity, and confusing the two, treating a velocity value as if it belongs in the acceleration formula, is the single most common mistake at this level. Time must be a positive number. If an object is slowing down or reversing direction, v_final minus v_initial will be negative, and that negative sign is meaningful, it shows deceleration or a direction reversal, so carry it through rather than dropping it. If a word problem gives distance in kilometers or velocity in kilometers per hour, convert everything to meters and meters per second first and show that conversion as its own visible step before touching the main formula. If I chose solve for average velocity, write v = d / t with the known distance and time substituted in, then divide to get velocity in meters per second. If I chose solve for average acceleration, write a = (v_final - v_initial) / t, calculate the change in velocity, v_final minus v_initial, as its own explicit step before dividing by time, then divide to get acceleration in meters per second squared, and state whether the sign indicates speeding up, slowing down, or reversing direction based on how it compares to the direction of motion. If I chose solve for a missing quantity given the formula, such as distance, time, or one of the two velocities, isolate that specific variable algebraically first, for example v_initial = v_final - (a x t), before substituting any numbers. In every case, keep the algebraic isolation step and the numeric substitution step visibly separate instead of jumping straight from the formula to a final number. Once you have a value, verify it. Substitute every quantity, including whichever one you just solved for, back into the original formula you used, recalculate both sides independently, and confirm they match, including the sign. If they don't match, say so, trace back through the isolation and substitution steps to find where the error happened, and redo that step instead of adjusting the final number to make it fit. If I chose explain the difference between velocity and acceleration with a worked example, start with the concepts themselves in one plain contrast: velocity tells you how fast position is changing and in what direction, acceleration tells you how fast velocity itself is changing, and an object can be moving quickly with zero acceleration, constant velocity, or moving slowly with large acceleration, so speed alone never tells you the acceleration. Then pick a concrete example, using [KNOWN_VALUES] if I gave you real numbers, or falling back to a simple scenario like a car that goes from 5 meters per second to 25 meters per second in 4 seconds if I left that generic, and tell me which one you picked. Walk through both formulas as they apply to that example with the same discipline described above, so the explanation and the worked proof of it reinforce each other. If the original input was a word problem, translate the final number back into that problem's own language, such as "the cyclist accelerates at 2 meters per second squared," instead of leaving it as a bare value with no connection to what was actually being asked.
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Get Early AccessA car cruising at a steady 100 km/h on the highway has zero acceleration. A go-kart crawling away from a stop at 5 km/h has plenty. Speed alone never tells you which is accelerating, because velocity measures how fast position changes and acceleration measures how fast velocity itself changes, two different rates layered on top of each other.
Give it your own [WORD_PROBLEM] or a set of [KNOWN_VALUES] and it solves for average velocity, average acceleration, or whichever piece is missing from either formula. It states up front which formula actually fits what you're solving for, since plugging a velocity into the acceleration slot is the most common way this goes wrong. A negative result when an object slows down or reverses gets carried through instead of dropped, kilometers and kilometers per hour get converted to meters and meters per second first, and the final answer gets checked against the original formula.
Ask for the explain mode instead and it contrasts both ideas side by side with a worked example, a car speeding up over a few seconds. Keep a running record in the Dock Editor, then move to the kinematics equations solver once a problem has more than one unknown and constant acceleration, or hand a solved acceleration to the Newton's second law solver to find the force behind it.
Start in the Dock Editor for an editable, saved copy, or paste this straight into ChatGPT, Claude, or Gemini. Set [MODE] to solve for average velocity, solve for average acceleration, solve for a missing quantity given the formula, or explain the difference with a worked example.
Paste a real scenario into [WORD_PROBLEM] and the known values get pulled from it automatically, or drop your known numbers directly into [KNOWN_VALUES].
Kilometers and kilometers per hour get converted to meters and meters per second before solving, and a negative sign from slowing down or reversing direction is carried through, not dropped.
The algebra that rearranges the chosen formula for your unknown happens on its own line, separate from plugging in the actual numbers.
The output plugs every value, sign included, back into the original formula and recalculates independently, so a wrong answer surfaces immediately.
Paste your homework word problem and pick velocity or acceleration to get a fully worked solution, with the two concepts kept clearly separate instead of blurred together.
See exactly how a negative sign shows up when an object slows down or reverses direction, and why dropping that sign midway through a calculation produces a wrong answer.
Use the simpler v = d/t and a = delta-v/delta-t formulas here before moving on to the full constant-acceleration kinematics equations.
Generate a model solution for any basic velocity or acceleration problem before class, with the algebra and the verification check both visible for students to follow.
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