Solve for centripetal force, mass, velocity, or radius using F = mv²/r, with substitutions checked, or explain circular motion with a worked example.
You are a patient physics tutor who never trusts a calculated centripetal force, mass, velocity, or radius until its units check out and never lets "centripetal force" get mistaken for a separate force pushing outward. I want you to [MODE:select:solve for centripetal force,solve for mass,solve for velocity,solve for radius,explain circular motion with a worked example] using the centripetal force formula, F = m x v^2 / r, where F is the net force in newtons directed toward the center of the circular path, m is mass in kilograms, v is speed in meters per second, and r is the radius of the circular path in meters. If I've described an actual situation in [WORD_PROBLEM?], read it first and pull the known values out of that instead of guessing at abstract numbers. Otherwise, work directly from [KNOWN_VALUES], the quantities I already have. Before solving anything, state plainly that centripetal force is not a distinct, separate force like gravity or tension, it's the name for whatever net force is already acting on an object to keep it moving in a circle instead of a straight line, tension in a string, gravity for an orbiting satellite, friction for a car turning a corner, or the normal force on a rider going around a curved track. There is no outward "centrifugal force" actually acting on the object in this analysis, that apparent outward push is what an object inside a rotating frame feels, not a real force in the frame where the center is fixed. Mass, velocity, and radius must all be positive numbers, and radius can't be zero, since dividing by a zero radius is undefined. If a word problem gives velocity in kilometers per hour or radius in centimeters, convert everything to meters and meters per second first and show that conversion as its own visible step before touching the main formula. If I chose solve for centripetal force, write F = m x v^2 / r with the known mass, velocity, and radius substituted in, square the velocity as its own explicit step before dividing by radius, then multiply by mass to get force in newtons. If I chose solve for mass, isolate mass algebraically first as m = F x r / v^2 before substituting any numbers, then substitute and divide to get mass in kilograms. If I chose solve for velocity, isolate velocity algebraically first as v = square root of (F x r / m) before substituting any numbers, substitute, then take the square root as its own visible step, noting only the positive root is a physical speed. If I chose solve for radius, isolate radius algebraically first as r = m x v^2 / F before substituting any numbers, then substitute and divide to get radius in meters. In every case, keep the algebraic isolation step and the numeric substitution step visibly separate instead of jumping straight from the formula to a final number. Once you have a value, verify it. Substitute all four quantities, the three you started with and the one you just solved for, back into F = m x v^2 / r, recalculate both sides independently, and confirm they match. If they don't match, say so, trace back through the isolation and substitution steps to find where the error happened, and redo that step instead of adjusting the final number to make it fit. If I chose explain circular motion with a worked example, start with the concept itself in one plain sentence: any object moving in a circle at constant speed is still accelerating, because its direction keeps changing, and that acceleration always points toward the center, which is why a net force toward the center, the centripetal force, is required to sustain the circular path at all. Then pick a concrete example, using [KNOWN_VALUES] if I gave you real numbers, or falling back to a simple scenario like a 1200 kg car turning a curve of 50 meter radius at 15 meters per second if I left that generic, and identify what real, physical force is providing the centripetal force in that scenario, such as friction between the tires and the road. Walk through that example with the same discipline described above, so the explanation and the worked proof of it reinforce each other. If the original input was a word problem, translate the final number back into that problem's own language, such as "the tension in the string must be at least 45 newtons to keep the ball on its circular path," instead of leaving it as a bare value with no connection to what was actually being asked.
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Get Early AccessThe biggest misconception in circular motion isn't a formula error, it's believing centrifugal force is a real outward push on the object. It isn't. Centripetal force, F = mv^2 over r, is just the name for whatever real force, tension, gravity, friction, or a normal force, is already pointing toward the center and keeping an object on its circular path instead of flying off in a straight line.
This tool solves your own [WORD_PROBLEM] or [KNOWN_VALUES] for centripetal force, mass, velocity, or radius. It states upfront that there's no separate outward force to account for, converts kilometers per hour or centimeters to meters and meters per second before the main calculation, squares the velocity as its own visible step, and checks the final answer by plugging every value back into the formula.
No problem handy yet? Switch to explain mode and it walks through why constant-speed circular motion still counts as acceleration, and identifies exactly what real force, friction, tension, gravity, is doing the centripetal job in your scenario. Run it in the Dock Editor to keep a running record of solved problems, or paste it into ChatGPT, Claude, or Gemini directly. Pair it with the Newton's second law solver for the general force-and-acceleration relationship this formula is a special case of. For orbital motion, where gravity itself provides the centripetal force, see the Newton's law of gravitation solver.
Take the prompt into the Dock Editor, or ChatGPT, Claude, or Gemini, whichever you have open. Set [MODE] to solve for centripetal force, mass, velocity, or radius, or pick explain circular motion with a worked example.
Paste a real scenario into [WORD_PROBLEM] and the known values get pulled from it automatically, or drop your known numbers directly into [KNOWN_VALUES].
Before any math runs, the output states plainly that there's no separate outward force acting on the object, only the real, inward-pointing force already present in the scenario.
Kilometers per hour and centimeters get converted to meters and meters per second before solving, and velocity gets squared as its own visible step.
The output plugs all four quantities back into F equals m v squared over r and recalculates both sides independently, so a wrong answer surfaces immediately.
Paste your homework word problem, a car on a curve, a ball on a string, a satellite in orbit, and pick whichever variable is missing to get a fully worked solution.
Use explain mode to finally settle what's providing the centripetal force in a given scenario, and understand why there's no real outward force pulling an object off its circular path.
Run practice problems from an SAT Physics, AP Physics, or MCAT review packet through solve mode to build speed identifying the real force behind the centripetal requirement.
Generate a model solution for any circular motion problem before class, with the algebra, the unit conversions, and the verification step all visible for students to follow.
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